(4x+1)(12x-1)(3x+2)(x+1)-4=0
(6x+5)^2 (3x+2)(x+1)=35
(x^2+x-5)/x+3x/(x^2+x-5)+4=0
(6-x)^4+(8-x)^4=16
21/(x^2-4x+10)-x^2+4x-6=0
x^2+1/x^2 -9/2 (x+1/x)+7=0
x^2-2x+7+3√((x+1)(x-3) )=0
2x^2-8x-3√(x^2-x-5)=12
√(x+3-4√(x-1)) +√(x+8-6√(x-1)) =1
√(3x-2)+√(x+7)=9
√(3x+4)+√(x-4)=2√x
√(9x^2+2x-3)+2=3x
∛(2-x)=1-√(x-1)
x^2-1=2x√(x^2-2x)
x^3-∛(2x-1)+1=0
∛x+∛(2x-3)=∛(12(x-1) )
√(x-1)+√(x+3)+2√((x-1)(x+3) )=4-2x
2∛(3x-2)+3√(2x+5)=-1
√(x^2-4x+5)+√(x-2)=1
√(1+x)-3∜(1-x^2 )+2√(1-x)=0